mode=link and full path to dependent shared library?

[Tim Mooney]

Can someone point me to the place in the docs that explains libtool's
handling of --mode=link when a dependent shared library is specified by
full path?  I'm having trouble finding it.

I'm talking about a situation like this:

/bin/sh ./libtool --tag=CXX --mode=link cxx  -some_compiler_flags -o libfoo.la 
-rpath /path/to/lib -version-info 16:3:1 -no-undefined foo.lo bar.lo baz.lo 
/path/to/lib/libdep.so -llib2 -lc -rpath /path/to/lib


libtool should be creating libfoo.la (and both shared and archive libfoo
libraries) and should be linking against /path/to/lib/libdep.so, but it's
eliding the /path/to/lib/libdep.so from the shared library creation line.
I'm just trying to find where this behavior is discussed, so I can
understand why it's doing that.

Tim
--
Tim Mooney                              address@hidden
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