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Re: first barnumber


From: Stefan Thomas
Subject: Re: first barnumber
Date: Thu, 13 May 2010 08:07:53 +0200

o.k. sorry, my fault. didn't see it!

2010/5/12 Graham Percival <address@hidden>
You don't need to do any searching of the snippet repository.

1.  Go to:
http://lilypond.org/doc/v2.12/Documentation/user/lilypond/Bars#Bar-numbers
2.  Read the SECOND EXAMPLE ON THE PAGE.  The one right after
"selected snippets".

or, in the 2.13 docs,
1.  Go to:
http://lilypond.org/doc/v2.13/Documentation/notation/bars#Bar-numbers
2.  Read the SECOND EXAMPLE ON THE PAGE, which isn't even inside
the "selected snippets" section.  Or read the THIRD EXAMPLE ON THE
PAGE, which says how to do this even clearer.


Some things in lilypond are hard to do.  Some things are only in
the snippet repository.  But this is in the mainstream Notation
reference.

- Graham

On Wed, May 12, 2010 at 08:49:19AM +0200, Stefan Thomas wrote:
>    Dear community,
>    thank You for Your help.
>    I know now, how to do it.
>    Off course, Graham is in principle right: before answering questions, one
>    should read the manual.
>    But: I've read the manual and I've searched for it without success.
>    It was my fault not to search in the snippet repository.
>    So, thanks again,
>    Stefan
>
>    2010/5/11 Graham Percival <address@hidden>
>
>      On Tue, May 11, 2010 at 09:42:53PM +0200, Xavier Scheuer wrote:
>      > 2010/5/11 Graham Percival <address@hidden>:
>      >
>      > > Yes.
>      >
>      > I assumed that Stefan's question was not only "is it possible to..."
>      > but that it also included the implicit question "and how?".
>
>      Then he should have asked "how can I make lilypond print the first
>      bar number?".  To which my reply would have been "by reading the
>      very first snippet on the doc page about bar numbers.".
>      > Your answer was technically correct, but not that much helpful...
>
>      Have I ever claimed to be interested in helping users who don't
>      look at the documentation?
>
>      Cheers,
>      - Graham


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