Re: Multiple replacements in one regular expression?

[Urs Liska]

Am 21.01.2015 um 13:53 schrieb Johan Vromans:
> On Wed, 21 Jan 2015 11:23:40 +0100
> Urs Liska <address@hidden> wrote:
>
> > #(set! str
> >          (regexp-substitute/global #f "&" str
> >            'pre "\\&" 'post))
> >
> > However, this approach will get quite cumbersome (and expensive) when
> > there are numerous characters to be escaped. Therefore I'd like to know
> > if I can "fold" them in one regular expression substitution.
>
> I don't know what implementation of regular expression matching scheme
> uses, but you should be able to specify a character set (group of
> characters) to match, capture the matching character, and replace it by
> itself with "\\" prepended.

Hm, it's not as easy as that because the escaping can be quite 
different, e.g.

"&" -> "\&"
"\" -> "\textbackslash "
"[" -> "{[}"

etc.

So what I really need is:
match (&)(\)([)
and replace that with
(\&)(\textbackslash )({})

And I would be glad if I wouldn't have to do that with individual runs 
of regexp-substitute.

Urs

> -- Johan
>
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--
Urs Liska
www.openlilylib.org