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From: | Gianmaria Lari |
Subject: | Re: using \pushToTag and \removeWithTag consecutively |
Date: | Sat, 14 Apr 2018 15:40:20 +0200 |
On 14 April 2018 at 15:15, David Kastrup <address@hidden> wrote:Gianmaria Lari <address@hidden> writes:
> I don't understand the behaviour of this code:
>
> \version "2.19.81"
> var = {a \tag #'here {b} a}
> {\var} %Result: a b a
> {\removeWithTag #'here \var} %Result: a a
> {\pushToTag #'here b! \removeWithTag #'here \var} %Result: a a ; Expected:
> a b! a
>
>
> The result is:
>
> a b a - ok!
> a a - ok!
> a a - not ok; shouldn't be "a b! a" ??
\removeWithTag removes the tagged _expression_. Which includes the tag
itself.This was what I was afraid of :)Any idea how I can obtain the same effect? I would like to be able to substitute a note in a variable with another one.Of course I could use "\pushToTag ... noteA" when I need noteA and "\pushToTag ... noteB" when i need noteB but I would like that my variable make sense also when I don't use \pushToTag command.Thank you, g.
\version "2.19.81"var = {a \tag #'herea {} \tag #'hereb {b} a}{\pushToTag #'herea b! \removeWithTag #'hereb \var}
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