Re: Full measure rests does not display in partial measure

[Malte Meyn]

Am 19.11.19 um 18:34 schrieb Павел Буданов:
> <<
>     { \partial 4*3 b b b b b b b }
>     \\
>     { R1*3/4 R1 }
> > >
>
> How to solve subject problem? I did not find the answer in the archive.

A partial measure is partial, not full, so why do you want a full 
measure rest?

In 4/4 time the rest should be written as “r4 r2”.