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Re: combining chords in chords


From: Gianmaria Lari
Subject: Re: combining chords in chords
Date: Thu, 22 Apr 2021 23:43:13 +0200

Thank you Aaron and Valentin for your help and your codes.
It worked perfectly in my previous example. 
Is it possible to make it working also with tags?

Here is a bit of information.
In my code, I use tags to generate two different outputs, one for midi and one for layout.
So my variables are like this...

ja = {\tag #'midiOut <c e>8 \tag #'screenOut <c' e'>8}

...and my "score" part is like this:

\score { \keepWithTag #'screenOut \music \layout {} }
\score { \keepWithTag #'midiOut \music \midi{} }

In this way I can specify a visual representation that is very different from the midi output.

Now let's go back to my problem.
Here it is my code with tags:

\version "2.23.2"
ja = {\tag #'midiOut <c e>8 \tag #'screenOut <c' e'>8}
jb = {\tag #'midiOut <g b>8 \tag #'screenOut <g' b'>8 }

music = \new Voice \fixed c << \ja \jb >>

\score { \keepWithTag #'screenOut \music \layout {} }
\score { \keepWithTag #'midiOut \music \layout{} } %here \layout{} should be \midi{}

This works perfectly and generates two scores:

<< { \tag #'screenOut < c' e' >8 } { \tag #'screenOut < g' b' >8 } >>
<< { \tag #'midiOut   < c e >8   } { \tag #'midiOut   < g b >8   } >>

Now I would like to make it work also with a manual beam. These are the solution I tried that don't work:

music = \new Voice \fixed c << \ja [\jb] >> % trivial wrong solution

music = \new Voice \fixed c \mergeChords \ja \jb  % Aaron solution

music = \new Voice \fixed c \ja s[ \jb s] % Valentin solution

If you have any suggestion to fix it you're welcome.
Thanks, g.


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