Re: Separate a tuplet from the rest under a common beam

[Paul Scott]

Good to know.  Many many versions ago we could just nest square brackets.

Paul

On 12/14/22 09:24, Michael Werner wrote:

Resending to include the list ... oops.

Something like this, perhaps?

\version "2.23.82"

\relative  {
  \clef treble
  \key c \minor
  \time 2/4
  \tuplet 3/2 { g'16[( aes \set stemRightBeamCount = #1 g) } \set stemLeftBeamCount = #1 fis g] a8 b |
}

On Wed, Dec 14, 2022 at 10:42 AM Volodymyr Prokopyuk <volodymyrprokopyuk@gmail.com> wrote:

Hello,

Problem

How can I separate a \tuplet from two sixteenths using a common eightingth beam?

Example code

\version "2.23.81"

\relative {
  \clef treble
  \key c \minor
  \time 2/4
  \tuplet 3/2 { g'='16[( aes g) } fis g] a8 b |
}

Desired result

I've tried to adjust the baseMoment, beatStructure, subdivideBeats and strictBeatBeaming but without success.

Thank you very much,

Vlad