[Octave-bug-tracker] [bug #59979] Unexpected format for output from datevec

[Markus Mützel]

Follow-up Comment #17, bug #59979 (project octave):

Regarding the date with day 0 and month 0:
I see the following in Matlab R2020b:

>> datevec(-2:0.5:2)

ans =

    -1    12    29     0     0     0
    -1    12    29    12     0     0
    -1    12    30     0     0     0
    -1    12    30    12     0     0
     0     0     0     0     0     0
     0     0     0    12     0     0
     0     1     1     0     0     0
     0     1     1    12     0     0
     0     1     2     0     0     0

>> datevec(365:0.5:368)

ans =

     0    12    30     0     0     0
     0    12    30    12     0     0
     0    12    31     0     0     0
     0    12    31    12     0     0
     1     1     1     0     0     0
     1     1     1    12     0     0
     1     1     2     0     0     0


There seems to be no 31st of December in the year 1 BCE. But there is a 31st
of December in the year 0 CE.
I find that rather surprising because I assumed `datevec` returns the date and
time.
But it looks like others expect it to return something different.

>From Matlab's documentation:
> DateVector = datevec(t) converts the datetime or duration value t to a date
vector—that is, a numeric vector whose six elements represent the year,
month, day, hour, minute, and second components of t.


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