Re: 1D NDArray -> octave_value

[John W. Eaton]

On 14-Dec-2006, Teemu Ikonen wrote:

| On 12/14/06, John W. Eaton <address@hidden> wrote:
| > It should not be possible to create 1-d vectors in Octave, so this may
| > be a bug.  Are you using the CVS sources?  Can you please post a short
| > example that shows precisely how a vector like this can be created?
| 
| Sorry, I sent the previous mail before it was ready. I'm using Octave
| 2.9.9 in Debian and here's a testcase. This produces a 10 element 1D
| vector.
| 
| #include <octave/oct.h>
| 
| 
| DEFUN_DLD(bug, args, nargout, "bug")
| {
|   dim_vector dv;
|   octave_value retval;
| 
|   dv = dim_vector();
|   dv.resize(1);
|   dv.elem(0) = 10;
|   NDArray y(dv);
|   for(int i = 0; i < 10; i++) {
|     y(i) = 1.0;
|   }
| 
|   retval = octave_value(y).squeeze();
|   return retval;
| 
| }

You are not supposed to do that.  Every object created by Octave
should have at least two dimensions.  Should we modify the dim_vector
class to enforce that?  What should it do if you try to create a
dim_vector with less than two dimensions (error, warning)?

jwe