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Re: Comparison with NaN

From: Michael Goffioul
Subject: Re: Comparison with NaN
Date: Mon, 11 May 2009 18:51:59 +0100 
On Mon, May 11, 2009 at 10:06 AM, Jaroslav Hajek <address@hidden> wrote:
> here you are:
>
> sort ([NaN, 1, -1, 2, Inf]')

ans =

   NaN
    -1
     1
     2
   Inf

> sort ([NaN, 1, -1, 2, Inf], 2)

ans =

   NaN    -1     1     2   Inf


> sortrows ([NaN, 1, -1, 2, Inf]')

ans =

   NaN
    -1
     1
     2
   Inf


Michael.
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