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Is transpose costless?
From: |
Rik |
Subject: |
Is transpose costless? |
Date: |
Mon, 15 Jul 2019 08:47:03 -0700 |
jwe,
I had a question about optimization in the parser. If I write
x = x.';
is that effectively a costless operation that simply swaps the first two
values of the dimension vector? Or does Octave first create a temporary
intermediate (which is costless because of COW), but then the transpose
operator forces a deep copy to the intermediate, and then the final
assignment takes place (also potentially another deep copy).
--Rik
- Is transpose costless?,
Rik <=