Re: [Tinycc-devel] Strange sizeof construct

[Mike]

>>> printf("%d\n",sizeof(arr)[0]); // ok, but why?
Why should that be valid syntax?  Is C99 really weird or what?
(its a immediate value being used in place of a pointer.)

-Mike

Marc Andre Tanner wrote:
> On Wed, Nov 14, 2007 at 12:39:18AM +0100, grischka wrote:
> > > Could a C guru out there please tell me why the following works? 
> > > Extra points if you can explain why it makes sense.
> > >
> > > #include <stdio.h>
> > >
> > > int main(){
> > > int arr[10];
> > > printf("%d\n",sizeof arr[0]);  // ok
> > > printf("%d\n",sizeof(arr[0])); // ok
> > > printf("%d\n",sizeof(arr)[0]); // ok, but why?
> > > return 0;
> > > }
> > And what about that one:
> >
> >     printf("%d\n",sizeof (0)[arr]); 
>
> Yep even stranger. The good thing is that if you add another pair of
> parantheses tcc takes it and life is good.
>
>   printf("%d\n",sizeof((arr)[0]));
>   printf("%d\n",sizeof((0)[arr]));
>
> > -- gr
> Marc