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Re: default -g ??!?
From: |
Russell Shaw |
Subject: |
Re: default -g ??!? |
Date: |
Sun, 21 Nov 2010 02:17:48 +1100 |
User-agent: |
Mozilla/5.0 (X11; U; Linux i686; en-US; rv:1.9.1.15) Gecko/20101030 Icedove/3.0.10 |
On 20/11/10 06:10, MK wrote:
I have a FOSS project distributed by debian, and for quite I've been
using this in the Makefile.am under install-data-am:
-strip --strip-all $(bindir)/executable
Since I could not find a way to prevent the project being built -g, and
there is no need for this.
Use dh_strip
However, I have a new release and my packager at debian is now saying
they do not want strip used in makefiles.
How can I prevent -g from being used?
The normal debian packages are stripped by dh_strip, or not when
the debug-symbols debs are made. Therefore, the debian packager
wants control over that. Therefore, you don't need to worry about
stripping.
- Re: reword documentation about symbol stripping, (continued)
- Re: reword documentation about symbol stripping (was: default -g ??!?), Karl Berry, 2010/11/21
- Re: reword documentation about symbol stripping, Miles Bader, 2010/11/21
- Re: reword documentation about symbol stripping, Karl Berry, 2010/11/22
- Re: reword documentation about symbol stripping, MK, 2010/11/23
- Re: default -g ??!?, Alfred M. Szmidt, 2010/11/21
- Re: default -g ??!?, Warren Young, 2010/11/22
- Re: default -g ??!?, Miles Bader, 2010/11/20
Re: default -g ??!?,
Russell Shaw <=