Re: How do you echo a shell variable reference

[Eric Blake]

On 04/13/2015 04:24 PM, Arthur Schwarz wrote:
> 
> I am trying to echo:
>    echo 'exit $status' >> file
> 
> from the Makefile generated by Makefile.am. What I get is:
>    echo 'exit $status' >> file
> 
> in the Makefile, which is correct, but in execution (make check) I get
>    exit tatus
> 
> in file. I have tried variations of $status to no avail. Any idea how I can
> get the correct result in file?

The same as any other time you want a literal $ to be passed through to
the shell when writing Makefile snippets: escape the $ with another $,
so that 'make' won't try to treat it as an expansion of ${s} at make time:

foo:
        echo 'exit $$status' >> file

-- 
Eric Blake   eblake redhat com    +1-919-301-3266
Libvirt virtualization library http://libvirt.org