Why does this work

[Stephan Austermühle]

Hi,

I'd like to access the script name ($0) in a shell function. I can do
this with

        #!/opt/gnu/bin/bash

        function myfunction {
                set -- $0

                echo "Parameters: $*"
                echo "Count: $#"
                return 0
        }

        myfunction test bla blub

Invoking the script returns

        $ ./fct.sh a b c
        Parameters: ./fct.sh
        Count: 1

Removing the "set..." line returns

        $ ./fct.sh a b c
        Parameters: test bla blub
        Count: 3

My questions are:

- Why gives the "set" statement as listed above access to the script
  name?
- Why does this work with bash but not with ksh?

Thanks very much for your answer and please excuse the posting if this
isn't the right list.

Stephan