"declare" builtin creates local variables within functions

[hcz]

Configuration Information [Automatically generated, do not change]:
Machine: i386
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i386' 
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i386-pc-linux-gnu' 
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL 
-DHAVE_CONFIG_H  -I.  -I../bash -I../bash/include -I../bash/lib   -g -O2
uname output: Linux tazzelwurm 2.6.11hcz1 #2 Fri Mar 11 20:01:21 CET 2005 i686 
GNU/Linux
Machine Type: i386-pc-linux-gnu

Bash Version: 3.0
Patch Level: 16
Release Status: release

Description:

        When variables are created with the "declare" builtin while in
        a function, they go out of scope when the function is left.

Repeat-By:

    #!/bin/bash

    foo(){
        declare bar="y"
        echo local:
        declare -p bar
    }
    declare baz=12
    foo

    echo global:
    declare -p bar baz

  This outputs:
    local:
    declare -- bar="y"
    global:
    ./x.sh: line 12: declare: bar: not found
    declare -- baz="12"
   
Note: "bar" in the example above is not really handled like a generic
local variable.  If the variable is already known at global level, the
"declare" within the function assigns to the global.  So doing a
"bar=" before the "declare" is executed (even within the function)
makes the error disapper.


Thanks for your good job,

Heike