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unable to declare multiple empty arrays on one line in bash-3.1
From: |
Mike Frysinger |
Subject: |
unable to declare multiple empty arrays on one line in bash-3.1 |
Date: |
Mon, 12 Dec 2005 01:59:24 +0000 |
User-agent: |
Mutt/1.5.11 |
Configuration Information:
Machine: x86_64
OS: linux-gnu
Compiler: x86_64-pc-linux-gnu-gcc
Compilation CFLAGS: -DPROGRAM='bash' -DCONF_HOSTTYPE='x86_64'
-DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='x86_64-pc-linux-gnu'
-DCONF_VENDOR='pc' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash' -DSHELL
-DHAVE_CONFIG_H -I. -I. -I./include -I./lib -O2 -march=k8 -pipe
uname output: Linux vapier 2.6.14.2-grsec #2 PREEMPT Mon Nov 14 00:03:42 EST
2005 x86_64 AMD Athlon(tm) 64 Processor 3500+ AuthenticAMD GNU/Linux
Machine Type: x86_64-pc-linux-gnu
Bash Version: 3.1
Patch Level: 0
Release Status: release
Description:
attempting to declare multiple local empty arrays fails with bash-3.1.
for example, this works with bash-3.0:
func() { local -a foo=() bar=() ; }
but fails with bash-3.1 with this fun error:
bash: syntax error near unexpected token `('
however, this works:
func() { local -a foo=() ; local -a bar=() ; }
tested current Gentoo ebuild and vanilla tarball, both go boom
-mike
- unable to declare multiple empty arrays on one line in bash-3.1,
Mike Frysinger <=