Re: One cant insert a single quote into a variable with built-in substitution.

[Matthew Woehlke]

Damien Nadé wrote:
> I've tried to insert a single quote into a variable content. 
> With something like this : 
>
> bash-3.2$ foo=bar
> bash-3.2$ echo "${foo/%/'}"
>  > 
>
> If you look at that, you understand that > is the $PS2, so it means that
> bash is interpreting the single quote a special char.
>
> So, naturally, I've told myself : "just escape it". And I've tried
> that :
>
> bash-3.2$ foo=bar
> bash-3.2$ echo "${foo/%/\'}"
> bar\'
>
> But... what the hell ? The backslash belongs to the variable now ?
> So, I cant use it "as is", and if I escape it, the command doesnt do
> what I want anymore..
>
> Is that some kind of bug in the parser ?

Hmm... that seems to be a good question. Meanwhile, you can do this:
$ foo=bar
$ q="'"
$ echo "${foo/%/$q}"
bar'

--
Matthew
FOSS: Giving people the cage and it's blueprints, gratis. The "L" matters.