Re: how to pass arguments with space inside?

[Mike Frysinger]

On Thursday 09 April 2009 17:47:59 lehe wrote:
> Thanks Mike.

please do not top post

> Mike Frysinger wrote:
> > On Thursday 09 April 2009 16:46:27 lehe wrote:
> >> I was wondering how to pass arguments with space inside. For example, my
> >> bash script looks like:
> >>
> >> #!/bin/bash
> >> ARG_OPTS=""
> >> while [[ -n "$1" ]];
> >>         ARG_OPTS="${ARG_OPTS} $1"
> >>    shift
> >> done
> >>
> >> If I pass an argument like "--options='-t 0 -v 0'", then it would be
> >> splitted by the spaces inside, ie "--options='-t", "0", "-v" and "0".
> >>
> >> How can I achieve what I wish?
> >
> > use arrays
> >
> > $ f=( a "b c" d)
> > $ printf '%s\n' "${f[@]}"
> > a
> > b c
> > d
>
> Could you explain it a little? I don't quite get it. How to apply this to
> argument parsing?

instead of gathering stuff into the variable ARG_OPTS, declare it as a 
variable and gather it there:
declare -a ARG_OPTS
while [[ -n $1 ]] ; do
        ARG_OPTS[${#ARG_OPTS[@]}]="$1"
        shift
done

then use it like i showed and the argument grouping will be preserved:
"${ARG_OPTS[@]}"

i imagine there are plenty of bash array howtos out there if you google
-mike