Re: bash accepts script with incorrect syntax and goes into infinite loop

[Pierre Gaston]

On Fri, Oct 9, 2009 at 1:06 PM, <werner@suse.de> wrote:

> Configuration Information [Automatically generated, do not change]:
> Machine: i586
> OS: linux-gnu
> Compiler: gcc -I/usr/src/packages/BUILD/bash-4.0
> -L/usr/src/packages/BUILD/bash-4.0/../readline-6.0
> Compilation CFLAGS:  -DPROGRAM='bash' -DCONF_HOSTTYPE='i586'
> -DCONF_OSTYPE='linux-gnu' -DCONF_MACHTYPE='i586-suse-linux-gnu'
> -DCONF_VENDOR='suse' -DLOCALEDIR='/usr/share/locale' -DPACKAGE='bash'
> -DSHELL -DHAVE_CONFIG_H   -I.  -I. -I./include -I./lib   -O2 -march=i586
> -mtune=i686 -fmessage-length=0 -Wall -D_FORTIFY_SOURCE=2 -fstack-protector
> -funwind-tables -fasynchronous-unwind-tables -g -D_LARGEFILE64_SOURCE
> -D_FILE_OFFSET_BITS=64 -D_GNU_SOURCE -DRECYCLES_PIDS -Wall -g -std=gnu89
> -Wextra -Wno-unprototyped-calls -Wno-switch-enum -Wno-unused-variable
> -Wno-unused-parameter -ftree-loop-linear -pipe -fprofile-use
> uname output: Linux boole 2.6.27.19-3.2-pae #1 SMP 2009-02-25 15:40:44
> +0100 i686 i686 i386 GNU/Linux
> Machine Type: i586-suse-linux-gnu
>
> Bash Version: 4.0
> Patch Level: 24
> Release Status: release
>
> Description:
>        The subject says it all.  Report was from an other user
>        https://bugzilla.novell.com/show_bug.cgi?id=545001
>
> Repeat-By:
>        printf '%s\n%s\n' foo bar | while read NAME;
>        echo NAME=$NAME
>        do
>            echo blah
>        done
>

Not sure what is the incorrect syntax, and it seems normal that it goes into
an infinite loop since echo is always true.