Re: local variable escapes into trap

[Akim Demaille]

Le 29 déc. 09 à 17:35, Chet Ramey a écrit :

> On 12/29/09 4:19 AM, Akim Demaille wrote:
> > Hi!

Hi Chet!

> > On the following script, the local variable $name of bar() hides the
> > global $name when entering the trap.  I have observed that with  
> > several
> > versions of Bash, including
> >
> > > GNU bash, version 4.0.33(1)-release (i486-pc-linux-gnu)
>
> I believe that bash is correct.  When the `exit' builtin is invoked,  
> and
> the trap is executed, the shell is still executing in the function's
> context.  There was no `return', and running exit or a trap does not
> implicitly call it.

I figured this out, the behavior is understandable.  But is it really  
desirable?  It's one more reason to fear shell-scripts :(  You cannot  
trust the context in which the trap will be run, in particular if you  
want to read "global" variables (and I do understand that all  
variables, including those flagged with "local", are actually global).

> > FWIW, Zsh and Dash behave as I expected.
>
> FWIW, ksh93 behaves like bash.

Well, if this behavior is what you want, I have nothing to add :/

Thanks!