glitch in an old documentation-example

[Jasper]

Hello List,

Searching the net for a way to validate user input to be a well-formed
floating point number I found this example in the bash documentation,
on my system ( Debian-Etch with Bash version 3.1.17 ) it is 
located here: 

/usr/share/doc/bash/examples/functions/isnum2

it reads:


isnum2()
{
        case "$1" in
        '[-+]' | '')    return 1;;      # empty or bare `-' or `+'
        [-+]*[!0-9]*)   return 1;;      # non-digit with leading sign
        [-+]*)          return 0;;      # OK
        *[!0-9]*)       return 1;;      # non-digit
        *)              return 0;;      # OK
        esac
}

# this one handles floating point
isnum3()
{
        case "$1" in
        '')             return 1;;      # empty
        *[!0-9.+-]*)    return 1;;      # non-digit, +, -, or .
        *?[-+]*)        return 1;;      # sign as second or later char
        *.*.*)          return 1;;      # multiple decimal points
        *)              return 0;;      # OK
        esac
}

But, in the first example, in this line:

        '[-+]' | '')    return 1;;      # empty or bare `-' or `+'

the '[-+]' should be without quotes to work as intended.

Additionally, in the second example the "bare + or -" is not catched.

So in both examples the first line after 'case' should read:

        [-+] | '')    return 1;;      # empty or bare `-' or `+'

Thanks for your time and efforts,

Jasper Noë