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Re: basic pattern match Question..."newbie" doesn't understand (!@#$@$)

From: Chris F.A. Johnson
Subject: Re: basic pattern match Question..."newbie" doesn't understand (!@#$@$)
Date: Sun, 1 Aug 2010 23:11:28 -0400 (EDT)
User-agent: Alpine 2.00 (LMD 1167 2008-08-23) 
On Sun, 1 Aug 2010, Linda Walsh wrote:


I have:

w="/home/law/bin/package: line 5: type: xx: not found"

The =~ operator is suppose to use the RH Expr as a ext.-regex.

So why doesn't this match and print "not found"?

if [[ $w =~ ".*not found.*" ]]; then echo "not found"; fi

It prints nothing.  Seems like such a basic concept.   Sorry, this newbie
needs help on such trivial matters. :-(


   When quoted, the right-hand argument is matched as a string, not an
   expression.

--
   Chris F.A. Johnson, <http://cfajohnson.com>
   Author:
   Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
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