Re: Calling Bash with /S

[sweinberger]

Roman Rakus wrote:
> 
> On 06/22/2011 06:59 PM, sweinberger wrote:
>> Hi All,
>>
>> I am calling bash from dmake.  The make file initiates the call to bash
>> as
>> follows:
>>
>> /bin/bash /S /c ""
> /bin/bash -S -c ?
> Anyway, -S is not valid option in Fedora's bash version 4.1.7.
>> The command to execute is between the double quotes.  For instance
>>
>> In Make File:
>> @ls -l ./SomeDir/*
>>
>> Bash Command
>> /bin/bash /S /c "ls -l ./SomeDir/*"
>>
>> The /S from what I see enables regular expression processing in the bash
>> command line, but maybe I might be wrong.  In any event, the problem that
>> I
>> have is the asterisk.  Bash does not like it.  I tried escaping it with a
>> backslash up to nine levels but that did not work; should only require
>> one.
> Pathname expansion is on by default. Can be turned off by `set -f' or 
> invoking bash with `-f' option.
>> Yes, the actual command that I use is not ls.  In the real example, I am
>> using "rm -f", but ls is a good example too and safer for
>> experimentation.
>>
>> How do I write the command line, so that it works?  "ls -l ./SomeDir/\*"
>> does not work, nor anything else that I tried so far.
> Explain what means `does not work'. What it does?
>> Thanks in advance,
>>
>> Sarah
> 
> RR
> 
> 
> 

-- 
View this message in context: 
http://old.nabble.com/Calling-Bash-with--S-tp31904926p31911107.html
Sent from the Gnu - Bash mailing list archive at Nabble.com.