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RE: cond?true:false and division by 0


From: dnade.ext
Subject: RE: cond?true:false and division by 0
Date: Thu, 11 Aug 2011 10:22:49 +0200

        Hello

Sorry for the delay.

I've applied your expr-noeval.patch file to the bash-4.2.10-4.fc15 package 
provided by fedora.
The problem seems solved. :)

Thanks !

        D

--
Damien Nadé <dnade.ext@orange-ftgroup.com>
Astek Sud-Est pour France Télécom - FT/OF/OFA/DMGP/PORTAIL/DOP/DEV/EAQS
Sophia Antipolis - France / Tel : 04 97 12 86 20


> -----Message d'origine-----
> De : Chet Ramey [mailto:chet.ramey@case.edu]
> Envoyé : mercredi 3 août 2011 03:14
> À : NADE Damien Ext DMGP/PORTAIL
> Cc : chet.ramey@case.edu; bug-bash@gnu.org
> Objet : Re: cond?true:false and division by 0
> 
> On 8/1/11 8:47 PM, Chet Ramey wrote:
> > On 8/1/11 4:41 AM, dnade.ext@orange-ftgroup.com wrote:
> >>    Hello
> >>
> >> I wanted to check a variable before attempting to divide something by
> it, so I wrote :
> >>
> >> echo $(( foo==0?0:something/foo ))
> >>
> >> And bash 2, 3 and up to 4.2.10 version sent me a "division by 0" error.
> >>
> >> So, I've tested a static version of the statement :
> >>
> >> $ echo $(( 0==0?0:1/0 ))
> >> -bash: 0==0?0:1/0 : division by 0 (error token is " ")
> >>
> >> It looks like the "division by 0" happens whatever the condition
> result.
> >> Shouldn't it happen only if condition result make the computing go that
> far (like, FWIW, in zsh) ?
> >
> > Hmm...this looks like a precedence problem.  I'll take a look.
> 
> It's not actually a precedence problem.  The check for division by 0
> shouldn't take place when evaluation is suppressed.  (The bash
> arithmetic evaluator, like most others of its type, is parse-and-
> evaluate-on-the-fly, so all operands are evaluated.
> 
> Please try the attached patch and see if it works for you.


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