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Re: [bug] Command substitutions within C-style for loops. Semicolon caus


From: Chet Ramey
Subject: Re: [bug] Command substitutions within C-style for loops. Semicolon causes error.
Date: Sat, 29 Oct 2011 21:56:08 -0400
User-agent: Mozilla/5.0 (Macintosh; Intel Mac OS X 10.6; rv:7.0.1) Gecko/20110929 Thunderbird/7.0.1

On 10/29/11 1:21 AM, Dan Douglas wrote:
> It seems the Bash parser can't distinguish between the semicolon as a
> command separator list operator, and the arithmetic context delimiter of
> the C-style for loop. I realize this construct isn't particularly useful.
> ksh93 and zsh handle it as expected, but in Bash it causes a syntax error
> on my system.

Thanks for the report.  The code that creates the three parts of the
arithmetic for loop is pretty naive; I'm not surprised that it doesn't
handle this right.  It will be fixed in the next release of bash.

Chet

-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/



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