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| From: | John Kearney |
| Subject: | Re: Inconsistent quote and escape handling in substitution part of parameter expansions. |
| Date: | Tue, 28 Feb 2012 23:49:24 +0100 |
| User-agent: | Mozilla/5.0 (X11; Linux i686; rv:10.0) Gecko/20120129 Thunderbird/10.0 |
On 02/28/2012 11:44 PM, Chet Ramey wrote: > echo "$(echo '$bar')" actually these both output the same in bash echo "$(echo '$bar')" echo $(echo '$bar')
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