Re: Arithmetic assignment side-effects

[Andreas Schwab]

Chris Down <chris@chrisdown.name> writes:

> On 2013-08-03 17:04, Dan Douglas wrote:
>> Is it specified what the value of x should be after this expression?
>>
>> x=0; : $((x+=x=1))
>
> I don't know if it is specified in a standard (I suspect it may be undefined),
> but it looks pretty clear to me that the answer should be 2. Has anyone 
> proposed
> logic that would suggest it should be 1?

x+=a is the same as x=x+a.  Now replace a by (x=1) and it becomes
obvious that 1 is a perfectly valid outcome.

Andreas.

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Andreas Schwab, schwab@linux-m68k.org
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