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'declare +a -g' destroys local arrays
From: |
Arfrever Frehtes Taifersar Arahesis |
Subject: |
'declare +a -g' destroys local arrays |
Date: |
Thu, 22 Aug 2013 10:52:02 +0200 |
User-agent: |
KMail (GNU/Linux) |
I use bash 4.2.45.
`man bash` says:
"Using `+' instead of `-' turns off the attribute instead, with the exceptions
that +a may not be
used to destroy an array variable and +r will not remove the readonly
attribute."
However 'declare +a -g' destroys local arrays, which do not shadow global
arrays:
$ f() { local ARRAY=(a b c); declare -p ARRAY; declare +a -g ARRAY; declare -p
ARRAY; }
$ f
declare -a ARRAY='([0]="a" [1]="b" [2]="c")'
bash: declare: ARRAY: cannot destroy array variables in this way
bash: declare: ARRAY: not found
$ ARRAY=(x y z)
$ f
declare -a ARRAY='([0]="a" [1]="b" [2]="c")'
bash: declare: ARRAY: cannot destroy array variables in this way
declare -a ARRAY='([0]="a" [1]="b" [2]="c")'
--
Arfrever Frehtes Taifersar Arahesis
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- 'declare +a -g' destroys local arrays,
Arfrever Frehtes Taifersar Arahesis <=