Re: i++ cause bad return code when result is 1

[Chris F.A. Johnson]

On Tue, 27 Aug 2013, Chris Down wrote:

> On 2013-08-26 21:36, David Lehmann wrote:
> > My issue is that the resulting behavior in Exercise 1 does not make sense.
> >
> > The resulting value of i should have no bearing on the exit code.  If the
> > addition succeeded, the expression should return 0 (success).  If i was not
> > an integer (e.g. i=hello), then I expect (( i++ )) to return a non-zero
> > error code.
> >
> > ...IMHO, of course.
>
> That would be pretty much rewriting the entire way that (( works, since the
> whole point is that it returns a status based upon having a return value that
> is >0.

   Rather, that it is != 0

> Compare:
>
>    $ (( 0 )); echo "$?"
>    1
>    $ (( 1 )); echo "$?"
>    0

$ (( -1 )); echo "$?"
0

--
   Chris F.A. Johnson, <http://cfajohnson.com/>
   Author:
   Pro Bash Programming: Scripting the GNU/Linux Shell (2009, Apress)
   Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)