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Re: [doc] confusion over $0 and positional parameters
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From: |
Chet Ramey |
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Subject: |
Re: [doc] confusion over $0 and positional parameters |
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Date: |
Wed, 27 Aug 2014 08:45:48 -0400 |
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User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.9; rv:24.0) Gecko/20100101 Thunderbird/24.6.0 |
On 8/27/14, 8:06 AM, Stephane Chazelas wrote:
> In
>
> info -f bash -n 'Invoking Bash'
>
> we find:
>
>> `-c'
>> Read and execute commands from the first non-option ARGUMENT after
>> processing the options, then exit. Any remaining arguments are
>> assigned to the positional parameters, starting with `$0'.
True, it's careless wording. I will modify it.
The key is that the behavior makes `bash -c string command args' and
`bash command args' equivalent in how they set $0.
Chet
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/