[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]
Re: for ((i=0; i<3 && i!=1; i++))
From: |
Chet Ramey |
Subject: |
Re: for ((i=0; i<3 && i!=1; i++)) |
Date: |
Mon, 12 Jan 2015 11:38:25 -0500 |
User-agent: |
Mozilla/5.0 (Macintosh; Intel Mac OS X 10.10; rv:31.0) Gecko/20100101 Thunderbird/31.3.0 |
On 1/12/15 4:26 AM, l_j_f wrote:
> 1. bash version
> -sh-4.3# bash --version
> GNU bash, version 4.3.0(1)-release (arm-hisiv200-linux-gnu)
> Copyright (C) 2013 Free Software Foundation, Inc.
> License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>
> This is free software; you are free to change and redistribute it.
> There is NO WARRANTY, to the extent permitted by law.
>
> 2. the script
> #!/bin/bash
>
> main() {
> local idx
> local current=1
>
> for ((idx=0; idx<3 && idx != current; idx++)); do
> echo $idx
> done
> }
>
> main "$@"
>
> 3. the result
> -sh-4.3# ./test1.sh
> 0
> # I think it should be
> 0
> 2
Why? The for loop breaks when the condition tests false.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU chet@case.edu http://cnswww.cns.cwru.edu/~chet/