Re: declare in a function makes a variable unable to be found with declare -p in some cases

[Chet Ramey]

On 2/17/15 5:46 PM, Eduardo A. Bustamante López wrote:

> You're reporting the behavior of the master branch, but it seems to
> be already fixed in devel. I'm not sure about the inconsistency
> between:
> |   "$bash" -c 'declare -a a="()"; declare -p a'
> and
> |   "$bash" -c 'f(){ declare -a a="()"; declare -p a; }; f'
> 
> IMO these two should have the same behaviour. Chet will be able to
> clarify this.

Thanks for the prompt; this is something that was waiting for me to bump
the version number and use a check for the shell compatibility level.
It will be fixed in the next git push for the devel branch.

Chet
-- 
``The lyf so short, the craft so long to lerne.'' - Chaucer
                 ``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, ITS, CWRU    chet@case.edu    http://cnswww.cns.cwru.edu/~chet/