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extra \1 in declare -p
From: |
isabella parakiss |
Subject: |
extra \1 in declare -p |
Date: |
Mon, 20 Jul 2015 20:23:56 +0200 |
Hi, about this bug:
http://lists.gnu.org/archive/html/bug-bash/2003-03/msg00093.html
The fix was to add this in lib/sh/shquote.c
else if (c == CTLESC || c == CTLNUL)
*r++ = CTLESC;
I think the fix it was applied twice, it should only check this in the
prompt string, right?
Now declare -p produces output that can't be eval'ed.
$ var=$'x\1y\177z'; declare -p var | sed -n l
declare -- var="x\001\001y\001\177z"$
Removing lines 151-152 (from the 4.4 alpha branch) seems to fix this.
The duplicate code keeps checking the prompt in lines 297-298.
(${var@P} is expanded by that part so it should be fine...)
I hope it won't cause other problems.
---
xoxo iza
- extra \1 in declare -p,
isabella parakiss <=