Bash bug

[Weshakie Löwe]

When storing the value of code executed in a subshell the return value 
is always 0 if the variable is local.

Code example:

A(){
 local return_value="$(bash -c "exit 1")"
 echo $?
}

function A: returns 0 - even though obviously the return value is 1.

B(){
 return_value="$(bash -c "exit 1")"
 echo $?
}

function B: returns 1 - as expected, the only difference to function A 
being not using a local variable to store the value.



Best regards,

A happy bash user