Re: Bug? Explanation??

[Peter & Kelly Passchier]

I guess they are not equivalent, piping into bash opens a subshell, and
sourcing doesn't; these act differently:

echo exit |bash

echo exit >r; source r

Hope I've gotten it right now. Thanks,
Peter


On 31/12/2559 11:20, Peter & Kelly Passchier wrote:
> Thanks Dennis and Grisha! I understand.
> 
> I had thought that every line that is piped into bash is it's own shell
> alignment, but I understand it's more like sourcing, so these would be
> more or less equivalent, right?
> 
> r=23; echo $r; echo -e 'r=bc\necho $r' >r; source r
> 
> r=23; echo $r; echo -e 'r=bc\necho $r' |bash
> 
> Thanks again,
> Peter
> 
> 
> On 31/12/2559 11:07, Grisha Levit wrote:
>> On Fri, Dec 30, 2016 at 11:03 PM, PePa <peterkelly@passchier.net
>> <mailto:peterkelly@passchier.net>> wrote:
>>
>>     r=23; echo $r; echo -e "r=bc\necho $r" |bash
>>
>> You need to escape the |$| in the second echo statement so that |$r| is
>> not evaluated to |23| before being echoed.
>>
>> ​
>