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Re: Return from function depending on number of parameters
From: |
Greg Wooledge |
Subject: |
Re: Return from function depending on number of parameters |
Date: |
Mon, 6 Jul 2020 07:50:26 -0400 |
User-agent: |
Mutt/1.10.1 (2018-07-13) |
On Fri, Jul 03, 2020 at 07:00:54PM +0100, Chris Elvidge wrote:
> I've used 'return $((!$#))' and 'return $[!$#]' to return an error if no
> parameters given to function.
The problem with this is that it *always* returns from the function,
even when paramters are given.
If you actually want to do what you said, you need a conditional check
of some kind, either "if" or "||".
(($#)) || return 1
would be my preference, if you really do not want to give any kind of
error message to indicate *why* you are returning with a failure code.
If you want to add an error message, then I would go with "if".
if ((! $#)); then
echo "usage: myfunc arg1 ..." >&2
return 1
fi
- Re: Return from function depending on number of parameters, (continued)
- Re: Return from function depending on number of parameters, Lawrence Velázquez, 2020/07/04
- Re: Return from function depending on number of parameters, Chet Ramey, 2020/07/05
- Re: Return from function depending on number of parameters, Chris Elvidge, 2020/07/10
- Re: Return from function depending on number of parameters, Chet Ramey, 2020/07/10
- Re: Return from function depending on number of parameters, Greg Wooledge, 2020/07/10
Re: Return from function depending on number of parameters, Chris Elvidge, 2020/07/04
Re: Return from function depending on number of parameters, Eli Schwartz, 2020/07/03
Re: Return from function depending on number of parameters,
Greg Wooledge <=