increment & decrement error when variable is 0

[Jetzer, Bill]

Configuration Information [Automatically generated, do not change]:
Machine: x86_64
OS: linux-gnu
Compiler: gcc
Compilation CFLAGS: -march=x86-64 -mtune=generic -O2 -pipe 
-fstack-protector-strong -fno-plt 
-DDEFAULT_PATH_VALUE='/usr/local/sbin:/usr/local/bin:/usr/bin' 
-DSTANDARD_UTILS_PATH='/usr/bin' -DSYS_BASHRC='/etc/bash.bashrc' 
-DSYS_BASH_LOGOUT='/etc/bash.bash_logout' -DNON_INTERACTIVE_LOGIN_SHELLS 
-Wno-parentheses -Wno-format-security
uname output: Linux ThinkTank 5.9.8-2-MANJARO #1 SMP PREEMPT Wed Nov 18 
06:38:03 UTC 2020 x86_64 GNU/Linux
Machine Type: x86_64-pc-linux-gnu

Bash Version: 5.0
Patch Level: 18
Release Status: release

Description:
                The prefix and postfix versions of the increment (++) and 
decrement (--) operators return a non-zero exist status when the varable's 
value is zero.  This causes scripts to terminate if `set -e` is used in scripts 
(as in [bash strict 
mode](http://redsymbol.net/articles/unofficial-bash-strict-mode/)).  See [this 
answer](https://stackoverflow.com/a/59775569/12859753) on Stack Overflow.

Repeat-By:
                for ((i=-100; i<100; i++))
                do
                                x=$i;
                                ((--x)) || echo "err code $? on --x going from 
$i to $x";
                                x=$i;
                                ((x--)) || echo "err code $? on x-- going from 
$i to $x";
                                x=$i;
                                ((++x)) || echo "err code $? on ++x going from 
$i to $x";
                                x=$i;
                                ((x++)) || echo "err code $? on x++ going from 
$i to $x";
                done;

                Results:
err code 1 on ++x going from -1 to 0
err code 1 on x-- going from 0 to -1
err code 1 on x++ going from 0 to 1
err code 1 on --x going from 1 to 0

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