Re: No expansions performed while declaring an associative array using a list of keys and values

[Léa Gris]

Le 11/12/2020 à 13:08, Oğuz écrivait :
> I was trying the new features of bash 5.1 and came across this inconsistent
> behavior:
>
>      $ foo='1 2'
>      $ declare -A bar=($foo 3)
>      $ declare -p bar
>      declare -A bar=(["\$foo"]="3" )
>      $
>      $ bar+=($foo 3)
>      $ declare -p bar
>      declare -A bar=(["\$foo"]="3" ["1 2"]="3" )
>
> Is there a particular reason to avoid performing expansions in `declare -A
> bar=($foo 3)'?
>
> Oğuz

Look like coherent with other Bash specific constructs like previous 
associative array key syntax that does not split a key variable:

    foo='1 2'
    declare -A bar=([$foo]=3 )

Or double square bracket tests:

    foo='1 2'
    [[ $foo == '1 2' ]]

Did you try with?:

    # possibly originating read -a or mapfile
    declare -a foo=(1 2 )

    # Declare associative array from key value array above
    declare -A assoc=("${foo[@]}" 3)

--
Léa Gris