Re: No expansions performed while declaring an associative array using a list of keys and values

[Oğuz]

On Fri, Dec 11, 2020 at 4:15 PM Léa Gris <lea.gris@noiraude.net> wrote:

> Le 11/12/2020 à 13:08, Oğuz écrivait :
> > I was trying the new features of bash 5.1 and came across this
> inconsistent
> > behavior:
> >
> >      $ foo='1 2'
> >      $ declare -A bar=($foo 3)
> >      $ declare -p bar
> >      declare -A bar=(["\$foo"]="3" )
> >      $
> >      $ bar+=($foo 3)
> >      $ declare -p bar
> >      declare -A bar=(["\$foo"]="3" ["1 2"]="3" )
> >
> > Is there a particular reason to avoid performing expansions in `declare
> -A
> > bar=($foo 3)'?
> >
> > Oğuz
> >
>
> Look like coherent with other Bash specific constructs like previous
> associative array key syntax that does not split a key variable:
>
>      foo='1 2'
>      declare -A bar=([$foo]=3 )
>
> Word splitting and parameter expansion are different things.


> Or double square bracket tests:
>
>      foo='1 2'
>      [[ $foo == '1 2' ]]
>
> Did you try with?:
>
>      # possibly originating read -a or mapfile
>      declare -a foo=(1 2 )
>
>      # Declare associative array from key value array above
>      declare -A assoc=("${foo[@]}" 3)
>
>
Nah, this doesn't work either. Would be really useful if it did though.

    $ declare -a foo=(1 2 )
    $ declare -A assoc=("${foo[@]}" 3)
    $ declare -p assoc
    declare -A assoc=(["\"\${foo[@]}\""]="3" )


> --
> Léa Gris
>
>
>