Re: syntax error while parsing a case command within `$(...)'

[Oğuz]

16 Şubat 2021 Salı tarihinde Koichi Murase <myoga.murase@gmail.com> yazdı:
>
> bash -c ': $(case x in esac)'
> bash -c ': $(case x in (x) if :; then echo a; fi esac)'
> bash -c ': $(case x in (x) a() { echo a; } esac)'
> bash -c ': $(case x in (x) for ((i=0;i<10;i++)) { echo a; } esac)'
> bash -c ': $(case x in (x) while false; do echo a; done esac)'
> bash -c ': $(case x in (x) case y in (y) echo a;; esac esac)'
>

I'm lost. Are these even supposed to work outside command substitution? Why?


-- 
Oğuz