Re: syntax error while parsing a case command within `$(...)'

[Oğuz]

16 Şubat 2021 Salı tarihinde Koichi Murase <myoga.murase@gmail.com> yazdı:

> 2021年2月16日(火) 19:24 Oğuz <oguzismailuysal@gmail.com>:
> > XRAT Shell Grammar (  https://pubs.opengroup.org/
> onlinepubs/9699919799/xrat/V4_xcu_chap02.html#tag_23_02_10 ) explains
> that giving almost the same examples as we posted in this thread.
>
> Thank you, interesting! So, if I understand correctly, the following
> construct which Bash allows is finally disallowed by POSIX?
>
> $ if (false) then (echo x) else (echo y) fi


No, it is allowed.


>
> To summarize, the following cases are required by the POSIX standard
> to be correctly parsed?
>
> $ bash -c ': $(case x in esac)'
> $ bash -c ': $(case x in (x) if :; then echo a; fi esac)'
> $ bash -c ': $(case x in (x) a() { echo a; } esac)'
> $ bash -c ': $(case x in (x) { echo a; } esac)'
> $ bash -c ': $(case x in (x) while false; do echo a; done esac)'
> $ bash -c ': $(case x in (x) case y in (y) echo a;; esac esac)'


Yes.


>
> and this case
>
> $ bash -c ': $(case x in (x) (echo a) esac)'
>
> could be a Bash extension.
>

No.


-- 
Oğuz