Re: syntax error while parsing a case command within `$(...)'

[Dale R. Worley]

Oğuz <oguzismailuysal@gmail.com> writes:
>> Before we worry about what to change, I want to note that the original
>> example is syntactically incorrect.  The example is
>>
>>   $ bash -c ': $(case x in x) esac)'
>>
>> But the manual page makes it clear that each case must be ended with
>> ";;".
>
> `;;' is optional for the last case item.

The manual page (for my version) says it's required.  If, in some
certain circumstances, it works without, that's nice.  But there's no
commitment that it will work now, or in future releases.

> `case x in esac' (without the linebreak) works fine outside the command
> substitution.

The manual page (for my version) says that "esac" will be recognized in
positions where a simple command may appear.  If, in some other
circumstances, it works, that's nice.  But there's no commitment that it
will work now, or in future releases.

Now, if you want to advocate that it *should* always work, go ahead.
But that's a feature request, not a bug report.

Dale