|
From: | Chet Ramey |
Subject: | Re: `${@:0}' expands to `$0 $1 ...', even though `$0' is not a positional parameter |
Date: | Wed, 3 Mar 2021 10:04:02 -0500 |
User-agent: | Mozilla/5.0 (Macintosh; Intel Mac OS X 10.15; rv:78.0) Gecko/20100101 Thunderbird/78.8.0 |
On 3/3/21 9:59 AM, Oğuz wrote:
The manual says:A positional parameter is a parameter denoted by one or more digits, other than the single digit 0.And about `${@:offset:length}', this is what's written there:If parameter is @, the result is length positional parameters beginning at offset.
"If offset is 0, and the positional parameters are used, $0 is prefixed to the list." -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ``Ars longa, vita brevis'' - Hippocrates Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/
[Prev in Thread] | Current Thread | [Next in Thread] |