Re: [bugreport] declare -n z is inconsistent with the z

[Melvin]

Scratch that. This is probably not a bug. I got an explanation on
stackoverflow:
https://stackoverflow.com/questions/68692482/what-does-the-bash-builtin-declare-n-z-do-with-the-z-parameter

Thanks for the great work GNU!

I wish you a nice day.

With kindest regards,
Melvin




On Sun, Aug 8, 2021 at 3:27 PM Melvin <melvin.europe@gmail.com> wrote:

> From: m
> To: bug-bash@gnu.org
> Subject: declare -n z is inconsistent with the z
>
> Configuration Information [Automatically generated, do not change]:
> Machine: x86_64
> OS: linux-gnu
> Compiler: gcc
> Compilation CFLAGS: -g -O2
> -fdebug-prefix-map=/build/bash-a6qmCk/bash-5.0=. -fstack-protector-strong
> -Wformat -Werror=format-security -Wall -Wno-parentheses -Wno-format-security
> uname output: Linux m 5.11.0-25-generic #27~20.04.1-Ubuntu SMP Tue Jul 13
> 17:41:23 UTC 2021 x86_64 x86_64 x86_64 GNU/Linux
> Machine Type: x86_64-pc-linux-gnu
>
> Bash Version: 5.0
> Patch Level: 17
> Release Status: release
>
> Description:
> The `declare -n variable` call seems to have inconsistent behavior.
> Use the Repeat-By code to see a clear example.
>
> Repeat-By:
>
> Example code:
> ```bash
> declare -n z
> echo "${z}"  # "" (empty)
> z="somevalue"
> echo "${z}"  # "" (empty)
>
> declare -n z
> echo "${z}"  # "" (empty)
> z="somevalue"
> echo "${z}"  # "somevalue"
> ```
>
>