Re: in-line calls to functions cause "exit" in the function to act like "return"

[Alex fxmbsw7 Ratchev]

x=$( exit 2 ) ; printf $?\\n

On Sat, Dec 18, 2021, 17:03 Kerin Millar <kfm@plushkava.net> wrote:

> On Sat, 18 Dec 2021 13:07:03 +0000
> yesxorno via Bug reports for the GNU Bourne Again SHell <bug-bash@gnu.org>
> wrote:
>
> > Description:
> >
> > When 'exit' is executed in a function called to "in-line" its output to
> stdout, the 'exit' acts like return, leaving the function scope, but not
> terminating the bash process.
>
> It does, in fact, exit the subshell in question.
>
> >
> > Repeat-By:
> >
> > Sample script:
> >
> > #!/bin/bash
> >
> > set -x
> >
> > function bar()
> > {
> >     exit 1
> > }
> >
> > foo="$(bar)"
>
> Here, the use of a command substitution causes a subshell to be created.
> The command, exit 1, is not run by the shell that the kernel loaded to
> interpret your script.
>
> --
> Kerin Millar
>
>