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Re: declare -Aa var
From: |
Chet Ramey |
Subject: |
Re: declare -Aa var |
Date: |
Tue, 13 Feb 2024 11:31:46 -0500 |
User-agent: |
Mozilla Thunderbird |
On 2/7/24 1:48 AM, Grisha Levit wrote:
If given both the -a and -A flags and an existing scalar variable,
declare will assign both attributes to the variable:
$ V=X; declare -Aa V; echo $?
0
$ echo ${V@a}
aA
$ (declare -p V)
Segmentation fault: 11
For the time being, we'll make this an error instead of `last one wins'.
--
``The lyf so short, the craft so long to lerne.'' - Chaucer
``Ars longa, vita brevis'' - Hippocrates
Chet Ramey, UTech, CWRU chet@case.edu http://tiswww.cwru.edu/~chet/
- declare -Aa var, Grisha Levit, 2024/02/07
- Re: declare -Aa var,
Chet Ramey <=