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Re: declare -f does not output esac pattern correctly
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From: |
Emanuele Torre |
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Subject: |
Re: declare -f does not output esac pattern correctly |
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Date: |
Tue, 27 Feb 2024 12:23:41 +0100 |
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User-agent: |
Mutt/2.2.12 (2023-09-09) |
On Tue, Feb 27, 2024 at 04:10:06PM +0700, Robert Elz wrote:
> Date: Tue, 27 Feb 2024 00:50:46 +0100
> From: Emanuele Torre <torreemanuele6@gmail.com>
> Message-ID: <Zd0j1s452p-Vod6H@t420>
>
> | To use esac as a pattern you need to use the (esac) syntax,
>
> Or quote it
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> 'esac')
>
> (or similar).
>
> kre
>
No, then the pattern is 'esac' not esac.
In fact, declare -f will print 'esac' and not esac in that case; as it
would print 'es'ac instead of easc if you had used 'es'ac.
After expansion, those patterns are both always esac, but that is
entirely besides the point.
o/
emanuele6