Re: two instances of global from shared lib linked with -Bsymbolic

[Rafal Dabrowa]

On Tuesday 06 of April 2004 18:22, Ian Lance Taylor wrote:
> Using -Bsymbolic breaks language rules.  That is why it is not the
> default.  The option exists because it can make shared library code
> more efficient, for people who do not require strict adherence to
> normal variable usage.
>
> Why are you using -Bsymbolic?

I want to have the following behavior. I have created a shared library with a 
lot of functions and global variables exposed to others. But I don't want up 
to anybody would override my functions. Suppose I have two functions in my 
lib:

        void fun1() { ... }
        void fun2() { fun1(); ... }

Function fun2 invokes fun1. I want up to fun2 would always invoke fun1 from my 
library. It is surprising for me, that if I create fun1 in main program, then 
fun2 invokes fun1 from main program instead of library. From this reason I 
have added -Bsymbolic option.

But, this option caused that I can't access any global variable from library. 
If a library function changes a global from library (e.g. MyErrno), I can't 
see the varibale change in main program.


Do you know any solution ?


Rafal