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Re: ltdl, -ansi compiler flag and windows host
From: |
Bob Friesenhahn |
Subject: |
Re: ltdl, -ansi compiler flag and windows host |
Date: |
Sat, 14 Nov 2009 15:30:35 -0600 (CST) |
User-agent: |
Alpine 2.01 (GSO 1266 2009-07-14) |
On Sat, 14 Nov 2009, Roumen Petrov wrote:
Hi All,
The failed case if project with ltdl included. If the project is configured
with "-ansi" flag set to CFLAGS the build of installable ltdl fail with:
When -ansi is set compiler define __STRICT_ANSI__.
No idea how to fix and I don't know reasons for above expression. Why
__STRICT_ANSI__ is part of expression ?
I believe that the intention of GCC is that when -ansi is provided
that the compiler conforms to ANSI C. Note that for ANSI C, POSIX,
and OpenGroup Unix standards, requesting the standard compilation
environment *excludes* any interfaces and functionality which are not
provided by that specification. It is necessary to request a standard
which supplies everything which is needed. That is why such requests
are often not made. In this case, the Windows APIs for loading
modules are not available.
Bob
--
Bob Friesenhahn
address@hidden, http://www.simplesystems.org/users/bfriesen/
GraphicsMagick Maintainer, http://www.GraphicsMagick.org/